NECO 2018 GENERAL MATHEMATICS (OBJECTIVE & ESSAY ) ANSWERS NOW AVAILABLE HERE – June/July

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  1. ====================
    9a)
    let Xy represent the two digit number
    x-y=5 —–(i)
    3xy – (10x +y)=14
    3xy – 10x – y =14 —-(ii)
    from eqn (i)
    x=5+y
    3y(5+y)-10(5+y)-y=14
    15y+3y^2 – 50 – 10y – y =14
    3y^2 + 4y -50 = 14
    3y^2 + 4y -50 – 14 =0
    3y^2 + 4y – 64 =0
    3y^2 + 12y + 16y – 64 =0
    (3y^2 – 12y) (+16y – 64)=0
    by
    (y-4)+16(y-4)=0
    (y-4)=0
    9aii)
    (3y+16)(y-4)=0
    3y+16=0 or y-4=0
    3y=-16 or y=4
    y=-16/3 or y=4
    when y=4
    x=5+y
    x=5+4
    x=9
    the no is 94
    9b)u
    3-2x/4 + 2x-3/3
    =3(3-2x)+4(2x-3)/12
    =9-6x+8x-12/12
    =2x-2/12

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